1/* 2 * Copyright (c) 2001, 2012, Oracle and/or its affiliates. All rights reserved. 3 * DO NOT ALTER OR REMOVE COPYRIGHT NOTICES OR THIS FILE HEADER. 4 * 5 * This code is free software; you can redistribute it and/or modify it 6 * under the terms of the GNU General Public License version 2 only, as 7 * published by the Free Software Foundation. 8 * 9 * This code is distributed in the hope that it will be useful, but WITHOUT 10 * ANY WARRANTY; without even the implied warranty of MERCHANTABILITY or 11 * FITNESS FOR A PARTICULAR PURPOSE. See the GNU General Public License 12 * version 2 for more details (a copy is included in the LICENSE file that 13 * accompanied this code). 14 * 15 * You should have received a copy of the GNU General Public License version 16 * 2 along with this work; if not, write to the Free Software Foundation, 17 * Inc., 51 Franklin St, Fifth Floor, Boston, MA 02110-1301 USA. 18 * 19 * Please contact Oracle, 500 Oracle Parkway, Redwood Shores, CA 94065 USA 20 * or visit www.oracle.com if you need additional information or have any 21 * questions. 22 * 23 */ 24 25#include "precompiled.hpp" 26#include "utilities/intHisto.hpp" 27 28IntHistogram::IntHistogram(int est, int max) : _max(max), _tot(0) { 29 assert(0 <= est && est <= max, "Preconditions"); 30 _elements = new (ResourceObj::C_HEAP, mtInternal) GrowableArray<int>(est, true); 31 guarantee(_elements != NULL, "alloc failure"); 32} 33 34void IntHistogram::add_entry(int outcome) { 35 if (outcome > _max) outcome = _max; 36 int new_count = _elements->at_grow(outcome) + 1; 37 _elements->at_put(outcome, new_count); 38 _tot++; 39} 40 41int IntHistogram::entries_for_outcome(int outcome) { 42 return _elements->at_grow(outcome); 43} 44 45void IntHistogram::print_on(outputStream* st) const { 46 double tot_d = (double)_tot; 47 st->print_cr("Outcome # of occurrences %% of occurrences"); 48 st->print_cr("-----------------------------------------------"); 49 for (int i=0; i < _elements->length()-2; i++) { 50 int cnt = _elements->at(i); 51 if (cnt != 0) { 52 st->print_cr("%7d %10d %8.4f", 53 i, cnt, (double)cnt/tot_d); 54 } 55 } 56 // Does it have any max entries? 57 if (_elements->length()-1 == _max) { 58 int cnt = _elements->at(_max); 59 st->print_cr(">= %4d %10d %8.4f", 60 _max, cnt, (double)cnt/tot_d); 61 } 62 st->print_cr("-----------------------------------------------"); 63 st->print_cr(" All %10d %8.4f", _tot, 1.0); 64} 65