1#!/bin/sh
2# Get modification time of a file or directory and pretty-print it.
3# Copyright 1995, 1996, 1997 Free Software Foundation, Inc.
4# written by Ulrich Drepper <drepper@gnu.ai.mit.edu>, June 1995
5#
6# This program is free software; you can redistribute it and/or modify
7# it under the terms of the GNU General Public License as published by
8# the Free Software Foundation; either version 2, or (at your option)
9# any later version.
10#
11# This program is distributed in the hope that it will be useful,
12# but WITHOUT ANY WARRANTY; without even the implied warranty of
13# MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the
14# GNU General Public License for more details.
15#
16# You should have received a copy of the GNU General Public License
17# along with this program; if not, write to the Free Software Foundation,
18# Inc., 59 Temple Place - Suite 330, Boston, MA 02111-1307, USA.
19
20# As a special exception to the GNU General Public License, if you
21# distribute this file as part of a program that contains a
22# configuration script generated by Autoconf, you may include it under
23# the same distribution terms that you use for the rest of that program.
24
25# Prevent date giving response in another language.
26LANG=C
27export LANG
28LC_ALL=C
29export LC_ALL
30LC_TIME=C
31export LC_TIME
32
33# Get the extended ls output of the file or directory.
34# On HPUX /bin/sh, "set" interprets "-rw-r--r--" as options, so the "x" below.
35if ls -L /dev/null 1>/dev/null 2>&1; then
36  set - x`ls -L -l -d $1`
37else
38  set - x`ls -l -d $1`
39fi
40# The month is at least the fourth argument
41# (3 shifts here, the next inside the loop).
42shift
43shift
44shift
45
46# Find the month.  Next argument is day, followed by the year or time.
47month=
48until test $month
49do
50  shift
51  case $1 in
52    Jan) month=January; nummonth=1;;
53    Feb) month=February; nummonth=2;;
54    Mar) month=March; nummonth=3;;
55    Apr) month=April; nummonth=4;;
56    May) month=May; nummonth=5;;
57    Jun) month=June; nummonth=6;;
58    Jul) month=July; nummonth=7;;
59    Aug) month=August; nummonth=8;;
60    Sep) month=September; nummonth=9;;
61    Oct) month=October; nummonth=10;;
62    Nov) month=November; nummonth=11;;
63    Dec) month=December; nummonth=12;;
64  esac
65done
66
67day=$2
68
69# Here we have to deal with the problem that the ls output gives either
70# the time of day or the year.
71case $3 in
72  *:*) set `date`; eval year=\$$#
73       case $2 in
74	 Jan) nummonthtod=1;;
75	 Feb) nummonthtod=2;;
76	 Mar) nummonthtod=3;;
77	 Apr) nummonthtod=4;;
78	 May) nummonthtod=5;;
79	 Jun) nummonthtod=6;;
80	 Jul) nummonthtod=7;;
81	 Aug) nummonthtod=8;;
82	 Sep) nummonthtod=9;;
83	 Oct) nummonthtod=10;;
84	 Nov) nummonthtod=11;;
85	 Dec) nummonthtod=12;;
86       esac
87       # For the first six month of the year the time notation can also
88       # be used for files modified in the last year.
89       if (expr $nummonth \> $nummonthtod) > /dev/null;
90       then
91	 year=`expr $year - 1`
92       fi;;
93  *) year=$3;;
94esac
95
96# The result.
97echo $day $month $year
98