1main ()
2{
3  union
4    {
5      double d;
6      unsigned short i[sizeof (double) / sizeof (short)];
7    } u;
8  int a = 0;
9  int b = -5;
10  int j;
11
12  u.d = (double) a / b;
13
14  /* Look for the right pattern, but be sloppy since
15     we don't know the byte order.  */
16  for (j = 0; j < sizeof (double) / sizeof (short); j++)
17    {
18      if (u.i[j] == 0x8000)
19	exit (0);
20    }
21  abort ();
22}
23