1/* 2 * CDDL HEADER START 3 * 4 * The contents of this file are subject to the terms of the 5 * Common Development and Distribution License (the "License"). 6 * You may not use this file except in compliance with the License. 7 * 8 * You can obtain a copy of the license at usr/src/OPENSOLARIS.LICENSE 9 * or http://www.opensolaris.org/os/licensing. 10 * See the License for the specific language governing permissions 11 * and limitations under the License. 12 * 13 * When distributing Covered Code, include this CDDL HEADER in each 14 * file and include the License file at usr/src/OPENSOLARIS.LICENSE. 15 * If applicable, add the following below this CDDL HEADER, with the 16 * fields enclosed by brackets "[]" replaced with your own identifying 17 * information: Portions Copyright [yyyy] [name of copyright owner] 18 * 19 * CDDL HEADER END 20 */ 21 22/* 23 * Copyright 2006 Sun Microsystems, Inc. All rights reserved. 24 * Use is subject to license terms. 25 */ 26 27#pragma ident "%Z%%M% %I% %E% SMI" 28 29/* 30 * ASSERTION: 31 * Test circular declaration of translations 32 * 33 * SECTION: Translators/ Translator Declarations 34 * SECTION: Translators/ Translate Operator 35 */ 36 37#pragma D option quiet 38 39struct input_struct { 40 int i; 41 char c; 42}; 43 44struct output_struct { 45 int myi; 46 char myc; 47}; 48 49translator struct output_struct < struct input_struct ivar > 50{ 51 myi = ((struct input_struct ) ivar).i; 52 myc = ((struct input_struct ) ivar).c; 53}; 54 55translator struct input_struct < struct output_struct uvar > 56{ 57 i = ((struct output_struct ) uvar).myi; 58 c = ((struct output_struct ) uvar).myc; 59}; 60 61struct input_struct f1; 62struct output_struct f2; 63 64BEGIN 65{ 66 f1.i = 10; 67 f1.c = 'c'; 68 69 f2.myi = 100; 70 f2.myc = 'd'; 71 72 printf("Testing circular translations\n"); 73 forwardi = xlate < struct output_struct > (f1).myi; 74 forwardc = xlate < struct output_struct > (f1).myc; 75 backwardi = xlate < struct input_struct > (f2).i; 76 backwardc = xlate < struct input_struct > (f2).c; 77 78 printf("forwardi: %d\tforwardc: %c\n", forwardi, forwardc); 79 printf("backwardi: %d\tbackwardc: %c", backwardi, backwardc); 80 exit(0); 81} 82 83BEGIN 84/(10 == forwardi) && ('c' == forwardc) && (100 == backwardi) && 85 ('d' == backwardc)/ 86{ 87 exit(0); 88} 89 90BEGIN 91/(10 != forwardi) || ('c' != forwardc) || (100 != backwardi) || 92 ('d' != backwardc)/ 93{ 94 exit(1); 95} 96 97ERROR 98{ 99 exit(1); 100} 101