Searched +refs:fundamental +refs:mode (Results 1 - 4 of 4) sorted by relevance
| /macosx-10.9.5/emacs-92/emacs/etc/ |
| H A D | TUTORIAL.pl | 791 podstawowym (ang. fundamental); jest to tryb u�ywanym w�a�nie w
792 tej chwili. Jest to przyk�ad ,,trybu g��wnego'' (ang. major mode).
807 tryb lub go wy��czy�. Przyk�adem mo�e by� M-x fundamental-mode, kt�re
812 powiniene� u�y� trybu tekstowego (ang. text mode).
814 >> Napisz M-x text-mode<Return>.
846 automatycznego wype�niania (ang. auto fill mode). Je�li jest on
851 auto-fill-mode<Return>. Powt�rzenie tego polecenie powoduje wy��czenie
855 >> Napisz M-x auto-fill-mode<Return>. Wstaw potem wiele napis�w
1243 ;;; mode
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| /macosx-10.9.5/CPANInternal-140/Class-DBI/lib/Class/ |
| H A D | DBI.pm | 1456 database in transactional mode).
1960 =head2 the fundamental set() and get() methods
1968 These methods are the fundamental entry points for getting and setting
2022 autoupdate. When in autoupdate mode, every time one calls an accessor
3010 http://search.cpan.org/search?query=Class%3A%3ADBI&mode=module
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| /macosx-10.9.5/CPANInternal-140/Class-DBI-v3.0.17/lib/Class/ |
| H A D | DBI.pm | 1446 database in transactional mode).
1970 =head2 the fundamental set() and get() methods
1978 These methods are the fundamental entry points for getting and setting
2045 autoupdate. When in autoupdate mode, every time one calls an accessor
3161 http://search.cpan.org/search?query=Class%3A%3ADBI&mode=module
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| /macosx-10.9.5/Heimdal-323.92.1/lib/hcrypto/libtommath/ |
| H A D | tommath.tex | 3612 RSA and Diffie-Hellman public key algorithms, for example. Modular multiplication and squaring also appears as a fundamental operation in
5073 11. $mode \leftarrow 0, bitcnt \leftarrow 1, buf \leftarrow 0, digidx \leftarrow x.used - 1, bitcpy \leftarrow 0, bitbuf \leftarrow 0$ \\
5099 \hspace{3mm}12.5 if $mode = 0$ and $y = 0$ then goto step 12. \\
5100 \hspace{3mm}12.6 if $mode = 1$ and $y = 0$ then do \\
5106 \hspace{3mm}12.9 $mode \leftarrow 2$ \\
5115 \hspace{6mm}12.10.4 $bitcpy \leftarrow 0, bitbuf \leftarrow 0, mode \leftarrow 1$ \\
5118 13. If $mode = 2$ and $bitcpy > 0$ then do \\
5150 \item The variable $mode$ dictates how the bits of the exponent are interpreted.
5152 \item When $mode = 0$ the bits are ignored since no non-zero bit of the exponent has been seen yet. For example, if the exponent were simply
5154 \item When $mode
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