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1/* Copyright (C) 1991, 1993, 1996, 1997, 1999, 2000, 2003, 2004, 2006 Free
2   Software Foundation, Inc.
3
4   Based on strlen implementation by Torbjorn Granlund (tege@sics.se),
5   with help from Dan Sahlin (dan@sics.se) and
6   commentary by Jim Blandy (jimb@ai.mit.edu);
7   adaptation to memchr suggested by Dick Karpinski (dick@cca.ucsf.edu),
8   and implemented by Roland McGrath (roland@ai.mit.edu).
9
10NOTE: The canonical source of this file is maintained with the GNU C Library.
11Bugs can be reported to bug-glibc@prep.ai.mit.edu.
12
13This program is free software: you can redistribute it and/or modify it
14under the terms of the GNU General Public License as published by the
15Free Software Foundation; either version 3 of the License, or any
16later version.
17
18This program is distributed in the hope that it will be useful,
19but WITHOUT ANY WARRANTY; without even the implied warranty of
20MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the
21GNU General Public License for more details.
22
23You should have received a copy of the GNU General Public License
24along with this program.  If not, see <http://www.gnu.org/licenses/>.  */
25
26#ifndef _LIBC
27# include <config.h>
28#endif
29
30#include <string.h>
31
32#include <stddef.h>
33
34#if defined _LIBC
35# include <memcopy.h>
36#else
37# define reg_char char
38#endif
39
40#include <limits.h>
41
42#if HAVE_BP_SYM_H || defined _LIBC
43# include <bp-sym.h>
44#else
45# define BP_SYM(sym) sym
46#endif
47
48#undef memchr
49#undef __memchr
50
51/* Search no more than N bytes of S for C.  */
52void *
53__memchr (void const *s, int c_in, size_t n)
54{
55  const unsigned char *char_ptr;
56  const unsigned long int *longword_ptr;
57  unsigned long int longword, magic_bits, charmask;
58  unsigned reg_char c;
59  int i;
60
61  c = (unsigned char) c_in;
62
63  /* Handle the first few characters by reading one character at a time.
64     Do this until CHAR_PTR is aligned on a longword boundary.  */
65  for (char_ptr = (const unsigned char *) s;
66       n > 0 && (size_t) char_ptr % sizeof longword != 0;
67       --n, ++char_ptr)
68    if (*char_ptr == c)
69      return (void *) char_ptr;
70
71  /* All these elucidatory comments refer to 4-byte longwords,
72     but the theory applies equally well to any size longwords.  */
73
74  longword_ptr = (const unsigned long int *) char_ptr;
75
76  /* Bits 31, 24, 16, and 8 of this number are zero.  Call these bits
77     the "holes."  Note that there is a hole just to the left of
78     each byte, with an extra at the end:
79
80     bits:  01111110 11111110 11111110 11111111
81     bytes: AAAAAAAA BBBBBBBB CCCCCCCC DDDDDDDD
82
83     The 1-bits make sure that carries propagate to the next 0-bit.
84     The 0-bits provide holes for carries to fall into.  */
85
86  /* Set MAGIC_BITS to be this pattern of 1 and 0 bits.
87     Set CHARMASK to be a longword, each of whose bytes is C.  */
88
89  magic_bits = 0xfefefefe;
90  charmask = c | (c << 8);
91  charmask |= charmask << 16;
92#if 0xffffffffU < ULONG_MAX
93  magic_bits |= magic_bits << 32;
94  charmask |= charmask << 32;
95  if (8 < sizeof longword)
96    for (i = 64; i < sizeof longword * 8; i *= 2)
97      {
98	magic_bits |= magic_bits << i;
99	charmask |= charmask << i;
100      }
101#endif
102  magic_bits = (ULONG_MAX >> 1) & (magic_bits | 1);
103
104  /* Instead of the traditional loop which tests each character,
105     we will test a longword at a time.  The tricky part is testing
106     if *any of the four* bytes in the longword in question are zero.  */
107  while (n >= sizeof longword)
108    {
109      /* We tentatively exit the loop if adding MAGIC_BITS to
110	 LONGWORD fails to change any of the hole bits of LONGWORD.
111
112	 1) Is this safe?  Will it catch all the zero bytes?
113	 Suppose there is a byte with all zeros.  Any carry bits
114	 propagating from its left will fall into the hole at its
115	 least significant bit and stop.  Since there will be no
116	 carry from its most significant bit, the LSB of the
117	 byte to the left will be unchanged, and the zero will be
118	 detected.
119
120	 2) Is this worthwhile?  Will it ignore everything except
121	 zero bytes?  Suppose every byte of LONGWORD has a bit set
122	 somewhere.  There will be a carry into bit 8.  If bit 8
123	 is set, this will carry into bit 16.  If bit 8 is clear,
124	 one of bits 9-15 must be set, so there will be a carry
125	 into bit 16.  Similarly, there will be a carry into bit
126	 24.  If one of bits 24-30 is set, there will be a carry
127	 into bit 31, so all of the hole bits will be changed.
128
129	 The one misfire occurs when bits 24-30 are clear and bit
130	 31 is set; in this case, the hole at bit 31 is not
131	 changed.  If we had access to the processor carry flag,
132	 we could close this loophole by putting the fourth hole
133	 at bit 32!
134
135	 So it ignores everything except 128's, when they're aligned
136	 properly.
137
138	 3) But wait!  Aren't we looking for C, not zero?
139	 Good point.  So what we do is XOR LONGWORD with a longword,
140	 each of whose bytes is C.  This turns each byte that is C
141	 into a zero.  */
142
143      longword = *longword_ptr++ ^ charmask;
144
145      /* Add MAGIC_BITS to LONGWORD.  */
146      if ((((longword + magic_bits)
147
148	    /* Set those bits that were unchanged by the addition.  */
149	    ^ ~longword)
150
151	   /* Look at only the hole bits.  If any of the hole bits
152	      are unchanged, most likely one of the bytes was a
153	      zero.  */
154	   & ~magic_bits) != 0)
155	{
156	  /* Which of the bytes was C?  If none of them were, it was
157	     a misfire; continue the search.  */
158
159	  const unsigned char *cp = (const unsigned char *) (longword_ptr - 1);
160
161	  if (cp[0] == c)
162	    return (void *) cp;
163	  if (cp[1] == c)
164	    return (void *) &cp[1];
165	  if (cp[2] == c)
166	    return (void *) &cp[2];
167	  if (cp[3] == c)
168	    return (void *) &cp[3];
169	  if (4 < sizeof longword && cp[4] == c)
170	    return (void *) &cp[4];
171	  if (5 < sizeof longword && cp[5] == c)
172	    return (void *) &cp[5];
173	  if (6 < sizeof longword && cp[6] == c)
174	    return (void *) &cp[6];
175	  if (7 < sizeof longword && cp[7] == c)
176	    return (void *) &cp[7];
177	  if (8 < sizeof longword)
178	    for (i = 8; i < sizeof longword; i++)
179	      if (cp[i] == c)
180		return (void *) &cp[i];
181	}
182
183      n -= sizeof longword;
184    }
185
186  char_ptr = (const unsigned char *) longword_ptr;
187
188  while (n-- > 0)
189    {
190      if (*char_ptr == c)
191	return (void *) char_ptr;
192      else
193	++char_ptr;
194    }
195
196  return 0;
197}
198#ifdef weak_alias
199weak_alias (__memchr, BP_SYM (memchr))
200#endif
201