1/* The contents of this file are subject to the Netscape Public
2 * License Version 1.1 (the "License"); you may not use this file
3 * except in compliance with the License. You may obtain a copy of
4 * the License at http://www.mozilla.org/NPL/
5 *
6 * Software distributed under the License is distributed on an "AS
7 * IS" basis, WITHOUT WARRANTY OF ANY KIND, either express or
8 * implied. See the License for the specific language governing
9 * rights and limitations under the License.
10 *
11 * The Original Code is Mozilla Communicator client code, released March
12 * 31, 1998.
13 *
14 * The Initial Developer of the Original Code is Netscape Communications
15 * Corporation. Portions created by Netscape are
16 * Copyright (C) 1998 Netscape Communications Corporation. All
17 * Rights Reserved.
18 *
19 * Contributor(s):
20 *
21 */
22/**
23    File Name:          11.5.2.js
24    ECMA Section:       11.5.2 Applying the / operator
25    Description:
26
27    The / operator performs division, producing the quotient of its operands.
28    The left operand is the dividend and the right operand is the divisor.
29    ECMAScript does not perform integer division. The operands and result of all
30    division operations are double-precision floating-point numbers.
31    The result of division is determined by the specification of IEEE 754 arithmetic:
32
33      If either operand is NaN, the result is NaN.
34      The sign of the result is positive if both operands have the same sign, negative if the operands have different
35      signs.
36      Division of an infinity by an infinity results in NaN.
37      Division of an infinity by a zero results in an infinity. The sign is determined by the rule already stated above.
38      Division of an infinity by a non-zero finite value results in a signed infinity. The sign is determined by the rule
39      already stated above.
40      Division of a finite value by an infinity results in zero. The sign is determined by the rule already stated above.
41      Division of a zero by a zero results in NaN; division of zero by any other finite value results in zero, with the sign
42      determined by the rule already stated above.
43      Division of a non-zero finite value by a zero results in a signed infinity. The sign is determined by the rule
44      already stated above.
45      In the remaining cases, where neither an infinity, nor a zero, nor NaN is involved, the quotient is computed and
46      rounded to the nearest representable value using IEEE 754 round-to-nearest mode. If the magnitude is too
47      large to represent, we say the operation overflows; the result is then an infinity of appropriate sign. If the
48      magnitude is too small to represent, we say the operation underflows and the result is a zero of the appropriate
49      sign. The ECMAScript language requires support of gradual underflow as defined by IEEE 754.
50
51    Author:             christine@netscape.com
52    Date:               12 november 1997
53*/
54    var SECTION = "11.5.2";
55    var VERSION = "ECMA_1";
56    startTest();
57    var testcases = getTestCases();
58    var BUGNUMBER="111202";
59
60    writeHeaderToLog( SECTION + " Applying the / operator");
61    test();
62
63function test() {
64    for ( tc=0; tc < testcases.length; tc++ ) {
65        testcases[tc].passed = writeTestCaseResult(
66                            testcases[tc].expect,
67                            testcases[tc].actual,
68                            testcases[tc].description +" = "+
69                            testcases[tc].actual );
70
71        testcases[tc].reason += ( testcases[tc].passed ) ? "" : "wrong value ";
72    }
73    stopTest();
74    return ( testcases );
75}
76function getTestCases() {
77    var array = new Array();
78    var item = 0;
79
80   // if either operand is NaN, the result is NaN.
81
82    array[item++] = new TestCase( SECTION,    "Number.NaN / Number.NaN",    Number.NaN,     Number.NaN / Number.NaN );
83    array[item++] = new TestCase( SECTION,    "Number.NaN / 1",             Number.NaN,     Number.NaN / 1 );
84    array[item++] = new TestCase( SECTION,    "1 / Number.NaN",             Number.NaN,     1 / Number.NaN );
85
86    array[item++] = new TestCase( SECTION,    "Number.POSITIVE_INFINITY / Number.NaN",    Number.NaN,     Number.POSITIVE_INFINITY / Number.NaN );
87    array[item++] = new TestCase( SECTION,    "Number.NEGATIVE_INFINITY / Number.NaN",    Number.NaN,     Number.NEGATIVE_INFINITY / Number.NaN );
88
89    // Division of an infinity by an infinity results in NaN.
90
91    array[item++] = new TestCase( SECTION,    "Number.NEGATIVE_INFINITY / Number.NEGATIVE_INFINITY",    Number.NaN,   Number.NEGATIVE_INFINITY / Number.NEGATIVE_INFINITY );
92    array[item++] = new TestCase( SECTION,    "Number.POSITIVE_INFINITY / Number.NEGATIVE_INFINITY",    Number.NaN,   Number.POSITIVE_INFINITY / Number.NEGATIVE_INFINITY );
93    array[item++] = new TestCase( SECTION,    "Number.NEGATIVE_INFINITY / Number.POSITIVE_INFINITY",    Number.NaN,   Number.NEGATIVE_INFINITY / Number.POSITIVE_INFINITY );
94    array[item++] = new TestCase( SECTION,    "Number.POSITIVE_INFINITY / Number.POSITIVE_INFINITY",    Number.NaN,   Number.POSITIVE_INFINITY / Number.POSITIVE_INFINITY );
95
96    // Division of an infinity by a zero results in an infinity.
97
98    array[item++] = new TestCase( SECTION,    "Number.POSITIVE_INFINITY / 0",   Number.POSITIVE_INFINITY, Number.POSITIVE_INFINITY / 0 );
99    array[item++] = new TestCase( SECTION,    "Number.NEGATIVE_INFINITY / 0",   Number.NEGATIVE_INFINITY, Number.NEGATIVE_INFINITY / 0 );
100    array[item++] = new TestCase( SECTION,    "Number.POSITIVE_INFINITY / -0",  Number.NEGATIVE_INFINITY,   Number.POSITIVE_INFINITY / -0 );
101    array[item++] = new TestCase( SECTION,    "Number.NEGATIVE_INFINITY / -0",  Number.POSITIVE_INFINITY,   Number.NEGATIVE_INFINITY / -0 );
102
103    // Division of an infinity by a non-zero finite value results in a signed infinity.
104
105    array[item++] = new TestCase( SECTION,    "Number.NEGATIVE_INFINITY / 1 ",          Number.NEGATIVE_INFINITY,   Number.NEGATIVE_INFINITY / 1 );
106    array[item++] = new TestCase( SECTION,    "Number.NEGATIVE_INFINITY / -1 ",         Number.POSITIVE_INFINITY,   Number.NEGATIVE_INFINITY / -1 );
107    array[item++] = new TestCase( SECTION,    "Number.POSITIVE_INFINITY / 1 ",          Number.POSITIVE_INFINITY,   Number.POSITIVE_INFINITY / 1 );
108    array[item++] = new TestCase( SECTION,    "Number.POSITIVE_INFINITY / -1 ",         Number.NEGATIVE_INFINITY,   Number.POSITIVE_INFINITY / -1 );
109
110    array[item++] = new TestCase( SECTION,    "Number.NEGATIVE_INFINITY / Number.MAX_VALUE ",          Number.NEGATIVE_INFINITY,   Number.NEGATIVE_INFINITY / Number.MAX_VALUE );
111    array[item++] = new TestCase( SECTION,    "Number.NEGATIVE_INFINITY / -Number.MAX_VALUE ",         Number.POSITIVE_INFINITY,   Number.NEGATIVE_INFINITY / -Number.MAX_VALUE );
112    array[item++] = new TestCase( SECTION,    "Number.POSITIVE_INFINITY / Number.MAX_VALUE ",          Number.POSITIVE_INFINITY,   Number.POSITIVE_INFINITY / Number.MAX_VALUE );
113    array[item++] = new TestCase( SECTION,    "Number.POSITIVE_INFINITY / -Number.MAX_VALUE ",         Number.NEGATIVE_INFINITY,   Number.POSITIVE_INFINITY / -Number.MAX_VALUE );
114
115    // Division of a finite value by an infinity results in zero.
116
117    array[item++] = new TestCase( SECTION,    "1 / Number.NEGATIVE_INFINITY",   -0,             1 / Number.NEGATIVE_INFINITY );
118    array[item++] = new TestCase( SECTION,    "1 / Number.POSITIVE_INFINITY",   0,              1 / Number.POSITIVE_INFINITY );
119    array[item++] = new TestCase( SECTION,    "-1 / Number.POSITIVE_INFINITY",  -0,             -1 / Number.POSITIVE_INFINITY );
120    array[item++] = new TestCase( SECTION,    "-1 / Number.NEGATIVE_INFINITY",  0,              -1 / Number.NEGATIVE_INFINITY );
121
122    array[item++] = new TestCase( SECTION,    "Number.MAX_VALUE / Number.NEGATIVE_INFINITY",   -0,             Number.MAX_VALUE / Number.NEGATIVE_INFINITY );
123    array[item++] = new TestCase( SECTION,    "Number.MAX_VALUE / Number.POSITIVE_INFINITY",   0,              Number.MAX_VALUE / Number.POSITIVE_INFINITY );
124    array[item++] = new TestCase( SECTION,    "-Number.MAX_VALUE / Number.POSITIVE_INFINITY",  -0,             -Number.MAX_VALUE / Number.POSITIVE_INFINITY );
125    array[item++] = new TestCase( SECTION,    "-Number.MAX_VALUE / Number.NEGATIVE_INFINITY",  0,              -Number.MAX_VALUE / Number.NEGATIVE_INFINITY );
126
127    // Division of a zero by a zero results in NaN
128
129    array[item++] = new TestCase( SECTION,    "0 / -0",                         Number.NaN,     0 / -0 );
130    array[item++] = new TestCase( SECTION,    "-0 / 0",                         Number.NaN,     -0 / 0 );
131    array[item++] = new TestCase( SECTION,    "-0 / -0",                        Number.NaN,     -0 / -0 );
132    array[item++] = new TestCase( SECTION,    "0 / 0",                          Number.NaN,     0 / 0 );
133
134    // division of zero by any other finite value results in zero
135
136    array[item++] = new TestCase( SECTION,    "0 / 1",                          0,              0 / 1 );
137    array[item++] = new TestCase( SECTION,    "0 / -1",                        -0,              0 / -1 );
138    array[item++] = new TestCase( SECTION,    "-0 / 1",                        -0,              -0 / 1 );
139    array[item++] = new TestCase( SECTION,    "-0 / -1",                       0,               -0 / -1 );
140
141    // Division of a non-zero finite value by a zero results in a signed infinity.
142
143    array[item++] = new TestCase( SECTION,    "1 / 0",                          Number.POSITIVE_INFINITY,   1/0 );
144    array[item++] = new TestCase( SECTION,    "1 / -0",                         Number.NEGATIVE_INFINITY,   1/-0 );
145    array[item++] = new TestCase( SECTION,    "-1 / 0",                         Number.NEGATIVE_INFINITY,   -1/0 );
146    array[item++] = new TestCase( SECTION,    "-1 / -0",                        Number.POSITIVE_INFINITY,   -1/-0 );
147
148    array[item++] = new TestCase( SECTION,    "0 / Number.POSITIVE_INFINITY",   0,      0 / Number.POSITIVE_INFINITY );
149    array[item++] = new TestCase( SECTION,    "0 / Number.NEGATIVE_INFINITY",   -0,     0 / Number.NEGATIVE_INFINITY );
150    array[item++] = new TestCase( SECTION,    "-0 / Number.POSITIVE_INFINITY",  -0,     -0 / Number.POSITIVE_INFINITY );
151    array[item++] = new TestCase( SECTION,    "-0 / Number.NEGATIVE_INFINITY",  0,      -0 / Number.NEGATIVE_INFINITY );
152
153    return ( array );
154}
155