1/*
2* The contents of this file are subject to the Netscape Public
3* License Version 1.1 (the "License"); you may not use this file
4* except in compliance with the License. You may obtain a copy of
5* the License at http://www.mozilla.org/NPL/
6*
7* Software distributed under the License is distributed on an "AS
8* IS" basis, WITHOUT WARRANTY OF ANY KIND, either express or
9* implied. See the License for the specific language governing
10* rights and limitations under the License.
11*
12* The Original Code is mozilla.org code.
13*
14* The Initial Developer of the Original Code is Netscape
15* Communications Corporation.  Portions created by Netscape are
16* Copyright (C) 1998 Netscape Communications Corporation. All
17* Rights Reserved.
18*
19* Contributor(s): pschwartau@netscape.com
20* Date: 26 November 2000
21*
22*
23*SUMMARY: Passing a RegExp object to a RegExp() constructor.
24*This test arose from Bugzilla bug 61266. The ECMA3 section is:
25*
26*  15.10.4.1 new RegExp(pattern, flags)
27*
28*  If pattern is an object R whose [[Class]] property is "RegExp" and
29*  flags is undefined, then let P be the pattern used to construct R
30*  and let F be the flags used to construct R. If pattern is an object R
31*  whose [[Class]] property is "RegExp" and flags is not undefined,
32*  then throw a TypeError exception. Otherwise, let P be the empty string
33*  if pattern is undefined and ToString(pattern) otherwise, and let F be
34*  the empty string if flags is undefined and ToString(flags) otherwise.
35*
36*
37*The current test will check the first scenario outlined above:
38*
39*   "pattern" is itself a RegExp object R
40*   "flags"  is undefined
41*
42* We check that a new RegExp object obj2 defined from these parameters
43* is morally the same as the original RegExp object obj1. Of course, they
44* can't be equal as objects - so we check their enumerable properties...
45*
46* In this test, the initial RegExp object obj1 will not include a flag.  This test is
47* identical to test 15.10.4.1-1.js, except that here we use this syntax:
48*
49*                  obj2 = new RegExp(obj1, undefined);
50*
51* instead of:
52*
53*                  obj2 = new RegExp(obj1);
54*/
55//-------------------------------------------------------------------------------------------------
56var bug = '61266';
57var summary = 'Passing a RegExp object to a RegExp() constructor';
58var statprefix = 'Applying RegExp() twice to pattern ';
59var statsuffix =  '; testing property ';
60var singlequote = "'";
61var i = -1; var s = '';
62var obj1 = {}; var obj2 = {};
63var status = ''; var actual = ''; var expect = ''; var msg = '';
64var patterns = new Array();
65
66
67// various regular expressions to try -
68patterns[0] = '';
69patterns[1] = 'abc';
70patterns[2] = '(.*)(3-1)\s\w';
71patterns[3] = '(.*)(...)\\s\\w';
72patterns[4] = '[^A-Za-z0-9_]';
73patterns[5] = '[^\f\n\r\t\v](123.5)([4 - 8]$)';
74
75
76
77//-------------------------------------------------------------------------------------------------
78test();
79//-------------------------------------------------------------------------------------------------
80
81
82function test()
83{
84  enterFunc ('test');
85  printBugNumber (bug);
86  printStatus (summary);
87
88  for (i in patterns)
89  {
90    s = patterns[i];
91    status =getStatus(s);
92    obj1 = new RegExp(s);
93    obj2 = new RegExp(obj1, undefined);  // see introduction to bug
94
95    for (prop in obj2)
96    {
97      msg  = status +  quote(prop);
98      actual = obj2[prop];
99      expect = obj1[prop];
100      reportCompare (expect, actual, msg);
101    }
102  }
103
104  exitFunc ('test');
105}
106
107
108function getStatus(regexp)
109{
110  return (statprefix  +  quote(regexp) +  statsuffix);
111}
112
113
114function quote(text)
115{
116  return (singlequote  +  text  + singlequote);
117}