1/* 2* The contents of this file are subject to the Netscape Public 3* License Version 1.1 (the "License"); you may not use this file 4* except in compliance with the License. You may obtain a copy of 5* the License at http://www.mozilla.org/NPL/ 6* 7* Software distributed under the License is distributed on an "AS 8* IS" basis, WITHOUT WARRANTY OF ANY KIND, either express or 9* implied. See the License for the specific language governing 10* rights and limitations under the License. 11* 12* The Original Code is mozilla.org code. 13* 14* The Initial Developer of the Original Code is Netscape 15* Communications Corporation. Portions created by Netscape are 16* Copyright (C) 1998 Netscape Communications Corporation. All 17* Rights Reserved. 18* 19* Contributor(s): pschwartau@netscape.com 20* Date: 26 November 2000 21* 22* 23*SUMMARY: Passing a RegExp object to a RegExp() constructor. 24*This test arose from Bugzilla bug 61266. The ECMA3 section is: 25* 26* 15.10.4.1 new RegExp(pattern, flags) 27* 28* If pattern is an object R whose [[Class]] property is "RegExp" and 29* flags is undefined, then let P be the pattern used to construct R 30* and let F be the flags used to construct R. If pattern is an object R 31* whose [[Class]] property is "RegExp" and flags is not undefined, 32* then throw a TypeError exception. Otherwise, let P be the empty string 33* if pattern is undefined and ToString(pattern) otherwise, and let F be 34* the empty string if flags is undefined and ToString(flags) otherwise. 35* 36* 37*The current test will check the first scenario outlined above: 38* 39* "pattern" is itself a RegExp object R 40* "flags" is undefined 41* 42* We check that a new RegExp object obj2 defined from these parameters 43* is morally the same as the original RegExp object obj1. Of course, they 44* can't be equal as objects - so we check their enumerable properties... 45* 46* In this test, the initial RegExp object obj1 will not include a flag. This test is 47* identical to test 15.10.4.1-1.js, except that here we use this syntax: 48* 49* obj2 = new RegExp(obj1, undefined); 50* 51* instead of: 52* 53* obj2 = new RegExp(obj1); 54*/ 55//------------------------------------------------------------------------------------------------- 56var bug = '61266'; 57var summary = 'Passing a RegExp object to a RegExp() constructor'; 58var statprefix = 'Applying RegExp() twice to pattern '; 59var statsuffix = '; testing property '; 60var singlequote = "'"; 61var i = -1; var s = ''; 62var obj1 = {}; var obj2 = {}; 63var status = ''; var actual = ''; var expect = ''; var msg = ''; 64var patterns = new Array(); 65 66 67// various regular expressions to try - 68patterns[0] = ''; 69patterns[1] = 'abc'; 70patterns[2] = '(.*)(3-1)\s\w'; 71patterns[3] = '(.*)(...)\\s\\w'; 72patterns[4] = '[^A-Za-z0-9_]'; 73patterns[5] = '[^\f\n\r\t\v](123.5)([4 - 8]$)'; 74 75 76 77//------------------------------------------------------------------------------------------------- 78test(); 79//------------------------------------------------------------------------------------------------- 80 81 82function test() 83{ 84 enterFunc ('test'); 85 printBugNumber (bug); 86 printStatus (summary); 87 88 for (i in patterns) 89 { 90 s = patterns[i]; 91 status =getStatus(s); 92 obj1 = new RegExp(s); 93 obj2 = new RegExp(obj1, undefined); // see introduction to bug 94 95 for (prop in obj2) 96 { 97 msg = status + quote(prop); 98 actual = obj2[prop]; 99 expect = obj1[prop]; 100 reportCompare (expect, actual, msg); 101 } 102 } 103 104 exitFunc ('test'); 105} 106 107 108function getStatus(regexp) 109{ 110 return (statprefix + quote(regexp) + statsuffix); 111} 112 113 114function quote(text) 115{ 116 return (singlequote + text + singlequote); 117}