1/*-
2 * SPDX-License-Identifier: BSD-2-Clause
3 *
4 * Copyright (c) 2001 Alexey Zelkin <phantom@FreeBSD.org>
5 * All rights reserved.
6 *
7 * Redistribution and use in source and binary forms, with or without
8 * modification, are permitted provided that the following conditions
9 * are met:
10 * 1. Redistributions of source code must retain the above copyright
11 *    notice, this list of conditions and the following disclaimer.
12 * 2. Redistributions in binary form must reproduce the above copyright
13 *    notice, this list of conditions and the following disclaimer in the
14 *    documentation and/or other materials provided with the distribution.
15 *
16 * THIS SOFTWARE IS PROVIDED BY THE AUTHOR AND CONTRIBUTORS ``AS IS'' AND
17 * ANY EXPRESS OR IMPLIED WARRANTIES, INCLUDING, BUT NOT LIMITED TO, THE
18 * IMPLIED WARRANTIES OF MERCHANTABILITY AND FITNESS FOR A PARTICULAR PURPOSE
19 * ARE DISCLAIMED.  IN NO EVENT SHALL THE AUTHOR OR CONTRIBUTORS BE LIABLE
20 * FOR ANY DIRECT, INDIRECT, INCIDENTAL, SPECIAL, EXEMPLARY, OR CONSEQUENTIAL
21 * DAMAGES (INCLUDING, BUT NOT LIMITED TO, PROCUREMENT OF SUBSTITUTE GOODS
22 * OR SERVICES; LOSS OF USE, DATA, OR PROFITS; OR BUSINESS INTERRUPTION)
23 * HOWEVER CAUSED AND ON ANY THEORY OF LIABILITY, WHETHER IN CONTRACT, STRICT
24 * LIABILITY, OR TORT (INCLUDING NEGLIGENCE OR OTHERWISE) ARISING IN ANY WAY
25 * OUT OF THE USE OF THIS SOFTWARE, EVEN IF ADVISED OF THE POSSIBILITY OF
26 * SUCH DAMAGE.
27 */
28
29#include <ctype.h>
30#include <limits.h>
31#include <stddef.h>
32
33static const char nogrouping[] = { '\0' };
34
35/*
36 * Internal helper used to convert grouping sequences from string
37 * representation into POSIX specified form, i.e.
38 *
39 * "3;3;-1" -> "\003\003\177\000"
40 */
41
42const char *
43__fix_locale_grouping_str(const char *str)
44{
45	char *src, *dst;
46	char n;
47
48	if (str == NULL || *str == '\0') {
49		return nogrouping;
50	}
51
52	for (src = (char*)str, dst = (char*)str; *src != '\0'; src++) {
53
54		/* input string examples: "3;3", "3;2;-1" */
55		if (*src == ';')
56			continue;
57
58		if (*src == '-' && *(src+1) == '1') {
59			*dst++ = CHAR_MAX;
60			src++;
61			continue;
62		}
63
64		if (!isdigit((unsigned char)*src)) {
65			/* broken grouping string */
66			return nogrouping;
67		}
68
69		/* assume all numbers <= 99 */
70		n = *src - '0';
71		if (isdigit((unsigned char)*(src+1))) {
72			src++;
73			n *= 10;
74			n += *src - '0';
75		}
76
77		*dst = n;
78		/* NOTE: assume all input started with "0" as 'no grouping' */
79		if (*dst == '\0')
80			return (dst == (char*)str) ? nogrouping : str;
81		dst++;
82	}
83	*dst = '\0';
84	return str;
85}
86