bn_recp.c revision 296465
1/* crypto/bn/bn_recp.c */
2/* Copyright (C) 1995-1998 Eric Young (eay@cryptsoft.com)
3 * All rights reserved.
4 *
5 * This package is an SSL implementation written
6 * by Eric Young (eay@cryptsoft.com).
7 * The implementation was written so as to conform with Netscapes SSL.
8 *
9 * This library is free for commercial and non-commercial use as long as
10 * the following conditions are aheared to.  The following conditions
11 * apply to all code found in this distribution, be it the RC4, RSA,
12 * lhash, DES, etc., code; not just the SSL code.  The SSL documentation
13 * included with this distribution is covered by the same copyright terms
14 * except that the holder is Tim Hudson (tjh@cryptsoft.com).
15 *
16 * Copyright remains Eric Young's, and as such any Copyright notices in
17 * the code are not to be removed.
18 * If this package is used in a product, Eric Young should be given attribution
19 * as the author of the parts of the library used.
20 * This can be in the form of a textual message at program startup or
21 * in documentation (online or textual) provided with the package.
22 *
23 * Redistribution and use in source and binary forms, with or without
24 * modification, are permitted provided that the following conditions
25 * are met:
26 * 1. Redistributions of source code must retain the copyright
27 *    notice, this list of conditions and the following disclaimer.
28 * 2. Redistributions in binary form must reproduce the above copyright
29 *    notice, this list of conditions and the following disclaimer in the
30 *    documentation and/or other materials provided with the distribution.
31 * 3. All advertising materials mentioning features or use of this software
32 *    must display the following acknowledgement:
33 *    "This product includes cryptographic software written by
34 *     Eric Young (eay@cryptsoft.com)"
35 *    The word 'cryptographic' can be left out if the rouines from the library
36 *    being used are not cryptographic related :-).
37 * 4. If you include any Windows specific code (or a derivative thereof) from
38 *    the apps directory (application code) you must include an acknowledgement:
39 *    "This product includes software written by Tim Hudson (tjh@cryptsoft.com)"
40 *
41 * THIS SOFTWARE IS PROVIDED BY ERIC YOUNG ``AS IS'' AND
42 * ANY EXPRESS OR IMPLIED WARRANTIES, INCLUDING, BUT NOT LIMITED TO, THE
43 * IMPLIED WARRANTIES OF MERCHANTABILITY AND FITNESS FOR A PARTICULAR PURPOSE
44 * ARE DISCLAIMED.  IN NO EVENT SHALL THE AUTHOR OR CONTRIBUTORS BE LIABLE
45 * FOR ANY DIRECT, INDIRECT, INCIDENTAL, SPECIAL, EXEMPLARY, OR CONSEQUENTIAL
46 * DAMAGES (INCLUDING, BUT NOT LIMITED TO, PROCUREMENT OF SUBSTITUTE GOODS
47 * OR SERVICES; LOSS OF USE, DATA, OR PROFITS; OR BUSINESS INTERRUPTION)
48 * HOWEVER CAUSED AND ON ANY THEORY OF LIABILITY, WHETHER IN CONTRACT, STRICT
49 * LIABILITY, OR TORT (INCLUDING NEGLIGENCE OR OTHERWISE) ARISING IN ANY WAY
50 * OUT OF THE USE OF THIS SOFTWARE, EVEN IF ADVISED OF THE POSSIBILITY OF
51 * SUCH DAMAGE.
52 *
53 * The licence and distribution terms for any publically available version or
54 * derivative of this code cannot be changed.  i.e. this code cannot simply be
55 * copied and put under another distribution licence
56 * [including the GNU Public Licence.]
57 */
58
59#include <stdio.h>
60#include "cryptlib.h"
61#include "bn_lcl.h"
62
63void BN_RECP_CTX_init(BN_RECP_CTX *recp)
64{
65    BN_init(&(recp->N));
66    BN_init(&(recp->Nr));
67    recp->num_bits = 0;
68    recp->flags = 0;
69}
70
71BN_RECP_CTX *BN_RECP_CTX_new(void)
72{
73    BN_RECP_CTX *ret;
74
75    if ((ret = (BN_RECP_CTX *)OPENSSL_malloc(sizeof(BN_RECP_CTX))) == NULL)
76        return (NULL);
77
78    BN_RECP_CTX_init(ret);
79    ret->flags = BN_FLG_MALLOCED;
80    return (ret);
81}
82
83void BN_RECP_CTX_free(BN_RECP_CTX *recp)
84{
85    if (recp == NULL)
86        return;
87
88    BN_free(&(recp->N));
89    BN_free(&(recp->Nr));
90    if (recp->flags & BN_FLG_MALLOCED)
91        OPENSSL_free(recp);
92}
93
94int BN_RECP_CTX_set(BN_RECP_CTX *recp, const BIGNUM *d, BN_CTX *ctx)
95{
96    if (!BN_copy(&(recp->N), d))
97        return 0;
98    BN_zero(&(recp->Nr));
99    recp->num_bits = BN_num_bits(d);
100    recp->shift = 0;
101    return (1);
102}
103
104int BN_mod_mul_reciprocal(BIGNUM *r, const BIGNUM *x, const BIGNUM *y,
105                          BN_RECP_CTX *recp, BN_CTX *ctx)
106{
107    int ret = 0;
108    BIGNUM *a;
109    const BIGNUM *ca;
110
111    BN_CTX_start(ctx);
112    if ((a = BN_CTX_get(ctx)) == NULL)
113        goto err;
114    if (y != NULL) {
115        if (x == y) {
116            if (!BN_sqr(a, x, ctx))
117                goto err;
118        } else {
119            if (!BN_mul(a, x, y, ctx))
120                goto err;
121        }
122        ca = a;
123    } else
124        ca = x;                 /* Just do the mod */
125
126    ret = BN_div_recp(NULL, r, ca, recp, ctx);
127 err:
128    BN_CTX_end(ctx);
129    bn_check_top(r);
130    return (ret);
131}
132
133int BN_div_recp(BIGNUM *dv, BIGNUM *rem, const BIGNUM *m,
134                BN_RECP_CTX *recp, BN_CTX *ctx)
135{
136    int i, j, ret = 0;
137    BIGNUM *a, *b, *d, *r;
138
139    BN_CTX_start(ctx);
140    a = BN_CTX_get(ctx);
141    b = BN_CTX_get(ctx);
142    if (dv != NULL)
143        d = dv;
144    else
145        d = BN_CTX_get(ctx);
146    if (rem != NULL)
147        r = rem;
148    else
149        r = BN_CTX_get(ctx);
150    if (a == NULL || b == NULL || d == NULL || r == NULL)
151        goto err;
152
153    if (BN_ucmp(m, &(recp->N)) < 0) {
154        BN_zero(d);
155        if (!BN_copy(r, m))
156            return 0;
157        BN_CTX_end(ctx);
158        return (1);
159    }
160
161    /*
162     * We want the remainder Given input of ABCDEF / ab we need multiply
163     * ABCDEF by 3 digests of the reciprocal of ab
164     */
165
166    /* i := max(BN_num_bits(m), 2*BN_num_bits(N)) */
167    i = BN_num_bits(m);
168    j = recp->num_bits << 1;
169    if (j > i)
170        i = j;
171
172    /* Nr := round(2^i / N) */
173    if (i != recp->shift)
174        recp->shift = BN_reciprocal(&(recp->Nr), &(recp->N), i, ctx);
175    /* BN_reciprocal could have returned -1 for an error */
176    if (recp->shift == -1)
177        goto err;
178
179    /*-
180     * d := |round(round(m / 2^BN_num_bits(N)) * recp->Nr / 2^(i - BN_num_bits(N)))|
181     *    = |round(round(m / 2^BN_num_bits(N)) * round(2^i / N) / 2^(i - BN_num_bits(N)))|
182     *   <= |(m / 2^BN_num_bits(N)) * (2^i / N) * (2^BN_num_bits(N) / 2^i)|
183     *    = |m/N|
184     */
185    if (!BN_rshift(a, m, recp->num_bits))
186        goto err;
187    if (!BN_mul(b, a, &(recp->Nr), ctx))
188        goto err;
189    if (!BN_rshift(d, b, i - recp->num_bits))
190        goto err;
191    d->neg = 0;
192
193    if (!BN_mul(b, &(recp->N), d, ctx))
194        goto err;
195    if (!BN_usub(r, m, b))
196        goto err;
197    r->neg = 0;
198
199#if 1
200    j = 0;
201    while (BN_ucmp(r, &(recp->N)) >= 0) {
202        if (j++ > 2) {
203            BNerr(BN_F_BN_DIV_RECP, BN_R_BAD_RECIPROCAL);
204            goto err;
205        }
206        if (!BN_usub(r, r, &(recp->N)))
207            goto err;
208        if (!BN_add_word(d, 1))
209            goto err;
210    }
211#endif
212
213    r->neg = BN_is_zero(r) ? 0 : m->neg;
214    d->neg = m->neg ^ recp->N.neg;
215    ret = 1;
216 err:
217    BN_CTX_end(ctx);
218    bn_check_top(dv);
219    bn_check_top(rem);
220    return (ret);
221}
222
223/*
224 * len is the expected size of the result We actually calculate with an extra
225 * word of precision, so we can do faster division if the remainder is not
226 * required.
227 */
228/* r := 2^len / m */
229int BN_reciprocal(BIGNUM *r, const BIGNUM *m, int len, BN_CTX *ctx)
230{
231    int ret = -1;
232    BIGNUM *t;
233
234    BN_CTX_start(ctx);
235    if ((t = BN_CTX_get(ctx)) == NULL)
236        goto err;
237
238    if (!BN_set_bit(t, len))
239        goto err;
240
241    if (!BN_div(r, NULL, t, m, ctx))
242        goto err;
243
244    ret = len;
245 err:
246    bn_check_top(r);
247    BN_CTX_end(ctx);
248    return (ret);
249}
250