bn_recp.c revision 59191
1/* crypto/bn/bn_recp.c */
2/* Copyright (C) 1995-1998 Eric Young (eay@cryptsoft.com)
3 * All rights reserved.
4 *
5 * This package is an SSL implementation written
6 * by Eric Young (eay@cryptsoft.com).
7 * The implementation was written so as to conform with Netscapes SSL.
8 *
9 * This library is free for commercial and non-commercial use as long as
10 * the following conditions are aheared to.  The following conditions
11 * apply to all code found in this distribution, be it the RC4, RSA,
12 * lhash, DES, etc., code; not just the SSL code.  The SSL documentation
13 * included with this distribution is covered by the same copyright terms
14 * except that the holder is Tim Hudson (tjh@cryptsoft.com).
15 *
16 * Copyright remains Eric Young's, and as such any Copyright notices in
17 * the code are not to be removed.
18 * If this package is used in a product, Eric Young should be given attribution
19 * as the author of the parts of the library used.
20 * This can be in the form of a textual message at program startup or
21 * in documentation (online or textual) provided with the package.
22 *
23 * Redistribution and use in source and binary forms, with or without
24 * modification, are permitted provided that the following conditions
25 * are met:
26 * 1. Redistributions of source code must retain the copyright
27 *    notice, this list of conditions and the following disclaimer.
28 * 2. Redistributions in binary form must reproduce the above copyright
29 *    notice, this list of conditions and the following disclaimer in the
30 *    documentation and/or other materials provided with the distribution.
31 * 3. All advertising materials mentioning features or use of this software
32 *    must display the following acknowledgement:
33 *    "This product includes cryptographic software written by
34 *     Eric Young (eay@cryptsoft.com)"
35 *    The word 'cryptographic' can be left out if the rouines from the library
36 *    being used are not cryptographic related :-).
37 * 4. If you include any Windows specific code (or a derivative thereof) from
38 *    the apps directory (application code) you must include an acknowledgement:
39 *    "This product includes software written by Tim Hudson (tjh@cryptsoft.com)"
40 *
41 * THIS SOFTWARE IS PROVIDED BY ERIC YOUNG ``AS IS'' AND
42 * ANY EXPRESS OR IMPLIED WARRANTIES, INCLUDING, BUT NOT LIMITED TO, THE
43 * IMPLIED WARRANTIES OF MERCHANTABILITY AND FITNESS FOR A PARTICULAR PURPOSE
44 * ARE DISCLAIMED.  IN NO EVENT SHALL THE AUTHOR OR CONTRIBUTORS BE LIABLE
45 * FOR ANY DIRECT, INDIRECT, INCIDENTAL, SPECIAL, EXEMPLARY, OR CONSEQUENTIAL
46 * DAMAGES (INCLUDING, BUT NOT LIMITED TO, PROCUREMENT OF SUBSTITUTE GOODS
47 * OR SERVICES; LOSS OF USE, DATA, OR PROFITS; OR BUSINESS INTERRUPTION)
48 * HOWEVER CAUSED AND ON ANY THEORY OF LIABILITY, WHETHER IN CONTRACT, STRICT
49 * LIABILITY, OR TORT (INCLUDING NEGLIGENCE OR OTHERWISE) ARISING IN ANY WAY
50 * OUT OF THE USE OF THIS SOFTWARE, EVEN IF ADVISED OF THE POSSIBILITY OF
51 * SUCH DAMAGE.
52 *
53 * The licence and distribution terms for any publically available version or
54 * derivative of this code cannot be changed.  i.e. this code cannot simply be
55 * copied and put under another distribution licence
56 * [including the GNU Public Licence.]
57 */
58
59#include <stdio.h>
60#include "cryptlib.h"
61#include "bn_lcl.h"
62
63void BN_RECP_CTX_init(BN_RECP_CTX *recp)
64	{
65	BN_init(&(recp->N));
66	BN_init(&(recp->Nr));
67	recp->num_bits=0;
68	recp->flags=0;
69	}
70
71BN_RECP_CTX *BN_RECP_CTX_new(void)
72	{
73	BN_RECP_CTX *ret;
74
75	if ((ret=(BN_RECP_CTX *)Malloc(sizeof(BN_RECP_CTX))) == NULL)
76		return(NULL);
77
78	BN_RECP_CTX_init(ret);
79	ret->flags=BN_FLG_MALLOCED;
80	return(ret);
81	}
82
83void BN_RECP_CTX_free(BN_RECP_CTX *recp)
84	{
85	if(recp == NULL)
86	    return;
87
88	BN_free(&(recp->N));
89	BN_free(&(recp->Nr));
90	if (recp->flags & BN_FLG_MALLOCED)
91		Free(recp);
92	}
93
94int BN_RECP_CTX_set(BN_RECP_CTX *recp, const BIGNUM *d, BN_CTX *ctx)
95	{
96	BN_copy(&(recp->N),d);
97	BN_zero(&(recp->Nr));
98	recp->num_bits=BN_num_bits(d);
99	recp->shift=0;
100	return(1);
101	}
102
103int BN_mod_mul_reciprocal(BIGNUM *r, BIGNUM *x, BIGNUM *y, BN_RECP_CTX *recp,
104	     BN_CTX *ctx)
105	{
106	int ret=0;
107	BIGNUM *a;
108
109	BN_CTX_start(ctx);
110	if ((a = BN_CTX_get(ctx)) == NULL) goto err;
111	if (y != NULL)
112		{
113		if (x == y)
114			{ if (!BN_sqr(a,x,ctx)) goto err; }
115		else
116			{ if (!BN_mul(a,x,y,ctx)) goto err; }
117		}
118	else
119		a=x; /* Just do the mod */
120
121	BN_div_recp(NULL,r,a,recp,ctx);
122	ret=1;
123err:
124	BN_CTX_end(ctx);
125	return(ret);
126	}
127
128int BN_div_recp(BIGNUM *dv, BIGNUM *rem, BIGNUM *m, BN_RECP_CTX *recp,
129	     BN_CTX *ctx)
130	{
131	int i,j,ret=0;
132	BIGNUM *a,*b,*d,*r;
133
134	BN_CTX_start(ctx);
135	a=BN_CTX_get(ctx);
136	b=BN_CTX_get(ctx);
137	if (dv != NULL)
138		d=dv;
139	else
140		d=BN_CTX_get(ctx);
141	if (rem != NULL)
142		r=rem;
143	else
144		r=BN_CTX_get(ctx);
145	if (a == NULL || b == NULL || d == NULL || r == NULL) goto err;
146
147	if (BN_ucmp(m,&(recp->N)) < 0)
148		{
149		BN_zero(d);
150		BN_copy(r,m);
151		BN_CTX_end(ctx);
152		return(1);
153		}
154
155	/* We want the remainder
156	 * Given input of ABCDEF / ab
157	 * we need multiply ABCDEF by 3 digests of the reciprocal of ab
158	 *
159	 */
160	i=BN_num_bits(m);
161
162	j=recp->num_bits<<1;
163	if (j>i) i=j;
164	j>>=1;
165
166	if (i != recp->shift)
167		recp->shift=BN_reciprocal(&(recp->Nr),&(recp->N),
168			i,ctx);
169
170	if (!BN_rshift(a,m,j)) goto err;
171	if (!BN_mul(b,a,&(recp->Nr),ctx)) goto err;
172	if (!BN_rshift(d,b,i-j)) goto err;
173	d->neg=0;
174	if (!BN_mul(b,&(recp->N),d,ctx)) goto err;
175	if (!BN_usub(r,m,b)) goto err;
176	r->neg=0;
177
178#if 1
179	j=0;
180	while (BN_ucmp(r,&(recp->N)) >= 0)
181		{
182		if (j++ > 2)
183			{
184			BNerr(BN_F_BN_MOD_MUL_RECIPROCAL,BN_R_BAD_RECIPROCAL);
185			goto err;
186			}
187		if (!BN_usub(r,r,&(recp->N))) goto err;
188		if (!BN_add_word(d,1)) goto err;
189		}
190#endif
191
192	r->neg=BN_is_zero(r)?0:m->neg;
193	d->neg=m->neg^recp->N.neg;
194	ret=1;
195err:
196	BN_CTX_end(ctx);
197	return(ret);
198	}
199
200/* len is the expected size of the result
201 * We actually calculate with an extra word of precision, so
202 * we can do faster division if the remainder is not required.
203 */
204int BN_reciprocal(BIGNUM *r, BIGNUM *m, int len, BN_CTX *ctx)
205	{
206	int ret= -1;
207	BIGNUM t;
208
209	BN_init(&t);
210
211	BN_zero(&t);
212	if (!BN_set_bit(&t,len)) goto err;
213
214	if (!BN_div(r,NULL,&t,m,ctx)) goto err;
215	ret=len;
216err:
217	BN_free(&t);
218	return(ret);
219	}
220
221