(* Title: HOL/Proofs/Extraction/Greatest_Common_Divisor.thy Author: Stefan Berghofer, TU Muenchen Author: Helmut Schwichtenberg, LMU Muenchen *) section \Greatest common divisor\ theory Greatest_Common_Divisor imports QuotRem begin theorem greatest_common_divisor: "\n::nat. Suc m < n \ \k n1 m1. k * n1 = n \ k * m1 = Suc m \ (\l l1 l2. l * l1 = n \ l * l2 = Suc m \ l \ k)" proof (induct m rule: nat_wf_ind) case (1 m n) from division obtain r q where h1: "n = Suc m * q + r" and h2: "r \ m" by iprover show ?case proof (cases r) case 0 with h1 have "Suc m * q = n" by simp moreover have "Suc m * 1 = Suc m" by simp moreover have "l * l1 = n \ l * l2 = Suc m \ l \ Suc m" for l l1 l2 by (cases l2) simp_all ultimately show ?thesis by iprover next case (Suc nat) with h2 have h: "nat < m" by simp moreover from h have "Suc nat < Suc m" by simp ultimately have "\k m1 r1. k * m1 = Suc m \ k * r1 = Suc nat \ (\l l1 l2. l * l1 = Suc m \ l * l2 = Suc nat \ l \ k)" by (rule 1) then obtain k m1 r1 where h1': "k * m1 = Suc m" and h2': "k * r1 = Suc nat" and h3': "\l l1 l2. l * l1 = Suc m \ l * l2 = Suc nat \ l \ k" by iprover have mn: "Suc m < n" by (rule 1) from h1 h1' h2' Suc have "k * (m1 * q + r1) = n" by (simp add: add_mult_distrib2 mult.assoc [symmetric]) moreover have "l \ k" if ll1n: "l * l1 = n" and ll2m: "l * l2 = Suc m" for l l1 l2 proof - have "l * (l1 - l2 * q) = Suc nat" by (simp add: diff_mult_distrib2 h1 Suc [symmetric] mn ll1n ll2m [symmetric]) with ll2m show "l \ k" by (rule h3') qed ultimately show ?thesis using h1' by iprover qed qed extract greatest_common_divisor text \ The extracted program for computing the greatest common divisor is @{thm [display] greatest_common_divisor_def} \ instantiation nat :: default begin definition "default = (0::nat)" instance .. end instantiation prod :: (default, default) default begin definition "default = (default, default)" instance .. end instantiation "fun" :: (type, default) default begin definition "default = (\x. default)" instance .. end lemma "greatest_common_divisor 7 12 = (4, 3, 2)" by eval end