/* * Copyright (c) 2000-2001 Apple Computer, Inc. All rights reserved. * * @APPLE_OSREFERENCE_LICENSE_HEADER_START@ * * This file contains Original Code and/or Modifications of Original Code * as defined in and that are subject to the Apple Public Source License * Version 2.0 (the 'License'). You may not use this file except in * compliance with the License. The rights granted to you under the License * may not be used to create, or enable the creation or redistribution of, * unlawful or unlicensed copies of an Apple operating system, or to * circumvent, violate, or enable the circumvention or violation of, any * terms of an Apple operating system software license agreement. * * Please obtain a copy of the License at * http://www.opensource.apple.com/apsl/ and read it before using this file. * * The Original Code and all software distributed under the License are * distributed on an 'AS IS' basis, WITHOUT WARRANTY OF ANY KIND, EITHER * EXPRESS OR IMPLIED, AND APPLE HEREBY DISCLAIMS ALL SUCH WARRANTIES, * INCLUDING WITHOUT LIMITATION, ANY WARRANTIES OF MERCHANTABILITY, * FITNESS FOR A PARTICULAR PURPOSE, QUIET ENJOYMENT OR NON-INFRINGEMENT. * Please see the License for the specific language governing rights and * limitations under the License. * * @APPLE_OSREFERENCE_LICENSE_HEADER_END@ */ ; ; ; Strlen, optimized for PPC. The routine we use is 2-3x faster ; then the simple loop which checks each byte for zero. ; For 0- and 1-byte strings, the simple routine is faster, but ; only by a few cycles. The algorithm used was adapted from the ; Mac OS 9 stdCLib strcopy routine, which was originally ; written by Gary Davidian. It relies on the following rather ; inobvious but very efficient test: ; ; y = dataWord + 0xFEFEFEFF ; z = ~dataWord & 0x80808080 ; if ( y & z ) = 0 then all bytes in dataWord are non-zero ; ; The test maps any non-zero byte to zeros and any zero byte to 0x80, ; with one exception: 0x01 bytes preceeding the first zero are also ; mapped to 0x80. ; #include #include ; ; int strlen(ptr) ; ; .align 5 .globl EXT(strlen) LEXT(strlen) andi. r4,r3,0x03 ; test alignment first mr r9,r3 ; store the original address for later use.... bne LalignSource ; align the source addr if not already aligned Llentry: lis r5,hi16(0xFEFEFEFF) lis r6,hi16(0x80808080) subi r3,r3,0x04 ; pre-decrement r3 for the lwzu ori r5,r5,lo16(0xFEFEFEFF) ; r5=0xFEFEFEFF ori r6,r6,lo16(0x80808080) ; r6=0x80808080 LLoop: lwzu r8,4(r3) ; get the first 4 bytes and increment address add r4,r5,r8 ; r4= data + 0xFEFEFEFF andc r7,r6,r8 ; r7= ~data & 0x80808080 and. r4,r4,r7 ; r4= r4 & r7 beq LLoop ; if r4 is zero, then all bytes are non-zero ; Now we know one of the bytes in r8 is zero, ; we just have to figure out which one. ; We have mapped 0 bytes to 0x80, and nonzero bytes to 0x00, ; with one exception: ; 0x01 bytes preceeding the first zero are also mapped to 0x80. ; So we have to mask out the 0x80s caused by 0x01s before ; counting leading zeroes to get the bytes in last word. rlwinm r5,r8,7,0,31 ; move 0x01 bits to 0x80 position subf r3,r9,r3 ; start to compute string length andc r4,r4,r5 ; turn off false hits from 0x0100 worst case cntlzw r7,r4 ; now we can count leading 0s srwi r7,r7,3 ; convert 0,8,16,24 to 0,1,2,3 add r3,r3,r7 ; add in nonzero bytes in last word blr ; We must align the source address for two reasons: to avoid spurious page ; faults, and for speed. ; r4 = low 2 bits of address (1,2, or 3) ; r3 = address ; r9 = original address (still same as r3) LalignSource: lbz r5,0(r3) ; get the first byte... subic. r4,r4,2 ; test for 1, 2 or 3 bytes addi r3,r3,1 ; increment address addi r6,r9,1 ; now r6==r3 cmpwi cr1,r5,0 ; zero? beq cr1,Lreturn ; if its zero return zero bgt Llentry ; address is aligned now if low bits were 3 lbz r5,0(r3) ; get the next byte... addi r3,r3,1 ; increment address cmpwi cr1,r5,0 ; zero? beq cr1,Lreturn ; if its zero return one beq Llentry ; addr is aligned now if low bits were 2 lbz r5,0(r3) ; get the next byte... addi r3,r3,1 ; increment address cmpwi cr1,r5,0 ; zero? bne cr1,Llentry ; not zero, continue check (now aligned) Lreturn: sub r3,r3,r6 ; get string length (0, 1, or 2) blr