ar/common/file.c

98 #define	PADSZ 8
196  * into PADSZ alignment within the file. This padding cannot be
221 	 * it to the archive ar_size. If they are within PADSZ bytes, then
223 	 * that no ELF section can fit into PADSZ bytes).
237 	if (padding >= PADSZ) {
242 		 * PADSZ bytes of ar_size, then this is the end of the object.
268 	 * (0 < pad < PADSZ) (ar(1) will never add more than this). A pad
269 	 * of 0 requires no action, and any other size above (PADSZ-1) means
279 	if (padding < PADSZ) {
723 	 * member data is aligned on PADSZ. If this is a debug build,
726 	assert(!is_elf || (pad(lseek(fd, 0, SEEK_CUR), PADSZ) == 0));
1004 		size += sizeof (struct ar_hdr) + long_strtbl.used + PADSZ;
1007 		size += sizeof_symtbl(nsyms, found_obj, 4) + PADSZ;
1013 		size += sizeof (struct ar_hdr) + fptr->ar_size + PADSZ;
1038 	char		pad_bytes[PADSZ];
1077 	 * need to arrange for its data to have an alignment of PADSZ. The
1087 			pad_cnt = pad(arsize + sizeof (struct ar_hdr), PADSZ);
1095 			pad_cnt = pad(arsize + sizeof (struct ar_hdr), PADSZ);
1205 	 * There can never be more tha PADSZ such bytes, so this number
1208 	for (pad_cnt = 0; pad_cnt < PADSZ; pad_cnt++)
1540 		 * data in the next item will have PADSZ alignment.
1550 			fptr->ar_padding = pad(psum + sum + hdrsize, PADSZ);