Lines Matching defs:curve

38     private static final int DRAWING_OP_TO = 1; // ie. curve, line, or quad
110 // This is where the curve to be processed is put. We give it
120 // dirty curve
121 final Curve curve;
131 this.curve = rdrCtx.curve;
254 // need 1 curve to approximate the circle section that joins omx,omy
307 // just return to avoid generating a flat curve:
313 // define the bezier curve we're computing.
681 // a curve with a cusp. What happens is that curveTo splits
682 // the input curve at the cusp, and passes it to this function.
710 // if p2-p1 and p4-p3 are parallel, that must mean this curve is a line
720 // offset curve (call it I) of the input curve B using a bezier curve Bp.
723 // 1. The computed curve Bp should go through I(0) and I(1). These are
737 // is true for any bezier curve; therefore, we get the equations
773 // for any bezier curve the vectors p2-p1 and p4-p3 are parallel to
826 // return the kind of curve in the right and left arrays.
842 // a curve with a cusp. What happens is that curveTo splits
843 // the input curve at the cusp, and passes it to this function.
856 // if p2-p1 and p4-p3 are parallel, that must mean this curve is a line
866 // for any bezier curve the vectors p2-p1 and p4-p3 are parallel to
887 // finds values of t where the curve in pts should be subdivided in order
888 // to get good offset curves a distance of w away from the middle curve.
895 // if the curve is already parallel to either axis we gain nothing
983 // this happens if the "curve" is just a point
1004 final int nSplits = findSubdivPoints(curve, mid, subdivTs, 8, lineWidth2);
1064 // this happens if the "curve" is just a point
1084 int nSplits = findSubdivPoints(curve, mid, subdivTs, 6, lineWidth2);
1130 // a stack of polynomial curves where each curve shares endpoints with