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  • only in /netgear-R7000-V1.0.7.12_1.2.5/ap/gpl/amule/wxWidgets-2.8.12/src/common/

Lines Matching refs:Jan

23  *    milliseconds since Jan 1. 1970 (the Unix Epoch) - so it is always
30 * possible, i.e. when the date is in the range Jan 1, 1970 to 2038
299 // this is the integral part of JDN of the midnight of Jan 1, 1970
300 // (i.e. JDN(Jan 1, 1970) = 2440587.5)
540 for ( mon = wxDateTime::Jan; mon < wxDateTime::Inv_Month; wxNextMonth(mon) )
930 case Jan:
931 ret = (flags == Name_Abbr ? wxT("Jan"): wxT("January"));
1208 dt.Set(1, Jan, year);
1218 dt.Set(6, Jan, 1974);
1382 // mktime() rather unintuitively fails for Jan 1, 1970 if the hour is
1509 // so that m_time will be 0 for the midnight of Jan 1, 1970 which is jdn
1850 // We suppose that when adding one month to Jan 31 we want to get Feb
1855 // Jan 30 + 1 month be - Feb 28 too or Feb 27 (assuming non leap year)?
1887 // Jan 4 always lies in the 1st week of the year
1888 wxDateTime dt(4, Jan, year);
1904 // Jan 4 always lies in the 1st week of the year
1905 wxDateTime dt(4, wxDateTime::Jan, year);
2126 int wdYearStart = wxDateTime(1, Jan, GetYear()).GetWeekDay();
2154 // if Jan 1 is Thursday or less, it is in the first week of this year
2157 // count the number of entire weeks between Jan 1 and this date
2164 else // Jan 1 is in the last week of the previous year
2167 if ( tm.mon == Jan && tm.mday < 8 - wdYearStart )
2206 for ( Month mon = Jan; mon < Inv_Month; wxNextMonth(mon) )
2440 // - 2038) whose Jan 1 falls on the same week day as the Jan 1
2455 // find the YEAR: normally, for any year X, Jan 1 or the
2456 // year X + 28 is the same weekday as Jan 1 of X (because
2764 if ( monName == _T("Jan") )
2765 mon = Jan;
3725 Tm tm2 = wxDateTime(1, Jan, tm.year).SetToYearDay(yday).GetTm();
4580 // for ( m = wxDateTime::Jan; m < wxDateTime::Inv_Month; wxNextMonth(m) )
4595 m = m == wxDateTime::Jan ? wxDateTime::Inv_Month