Lines Matching refs:ifnum
256 \def\smallbreak{\ifnum\lastpenalty<10000\par\ifdim\lastskip<\smallskipamount
258 \def\medbreak{\ifnum\lastpenalty<10000\par\ifdim\lastskip<\medskipamount
260 \def\bigbreak{\ifnum\lastpenalty<10000\par\ifdim\lastskip<\bigskipamount
358 \ifnum\outputpenalty>-20000 \else\dosupereject\fi
679 \ifnum\catcode`\^^M=\active \else
1034 \def_{\ifnum\fam=\slfam \_\else\sb\fi}%
1043 \def\mathbackslash{\ifnum\fam=\ttfam \mathchar"075C \else\backslash \fi}
1180 \ifnum\pdftexversion < 14
1187 \ifnum\pdftexversion<13
1192 \ifnum\pdftexversion < 14 \else
1304 \ifnum\lnkcount>0,\fi
1337 \ifnum\pdftexversion < 14
2302 \ifnum 0#1>0 \advance \leftskip by #1\mil \fi
2303 \ifnum 0#2>0 \tableindent=#2\mil \fi
2304 \ifnum 0#3>0 \advance \rightskip by #3\mil \fi
2356 \ifnum\lastpenalty<10000 \parskip=0in \fi
2391 % We need the \relax at the end of the \ifnum lines to stop TeX from
2394 \ifnum\lccode\expandafter`\thearg=0\relax
2398 \ifnum\lccode\expandafter`\thearg=\expandafter`\thearg\relax
2423 \ifnum\itemno=0
2436 \ifnum\itemno=0
2653 \ifnum\colcount=1
2802 \ifnum\doignorecount = 0 % We have just found the outermost @end.
3383 \ifnum\count255>9999 \nobreak \fi
3774 \ifnum\appendixno=`A A%
3775 \else\ifnum\appendixno=`B B%
3776 \else\ifnum\appendixno=`C C%
3777 \else\ifnum\appendixno=`D D%
3778 \else\ifnum\appendixno=`E E%
3779 \else\ifnum\appendixno=`F F%
3780 \else\ifnum\appendixno=`G G%
3781 \else\ifnum\appendixno=`H H%
3782 \else\ifnum\appendixno=`I I%
3783 \else\ifnum\appendixno=`J J%
3784 \else\ifnum\appendixno=`K K%
3785 \else\ifnum\appendixno=`L L%
3786 \else\ifnum\appendixno=`M M%
3787 \else\ifnum\appendixno=`N N%
3788 \else\ifnum\appendixno=`O O%
3789 \else\ifnum\appendixno=`P P%
3790 \else\ifnum\appendixno=`Q Q%
3791 \else\ifnum\appendixno=`R R%
3792 \else\ifnum\appendixno=`S S%
3793 \else\ifnum\appendixno=`T T%
3794 \else\ifnum\appendixno=`U U%
3795 \else\ifnum\appendixno=`V V%
3796 \else\ifnum\appendixno=`W W%
3797 \else\ifnum\appendixno=`X X%
3798 \else\ifnum\appendixno=`Y Y%
3799 \else\ifnum\appendixno=`Z Z%
3835 \ifnum \absseclevel<0 \chapterzzz{#2}%
3850 \ifnum \absseclevel<0 \appendixzzz{#2}%
3865 \ifnum \absseclevel<0 \unnumberedzzz{#2}%
4389 \ifnum \pageno>0 \global\pageno = \lastnegativepageno \fi
4655 \ifnum \lastpenalty=10000 \else
4662 \ifnum\lastpenalty<10000 \penalty-50 \fi
5064 \ifnum \lastpenalty=1 %
5092 \ifnum\lastpenalty<10000
5102 \ifnum\lastpenalty=10002 \penalty2000 \fi
5120 \ifnum\lastpenalty=10002 \penalty3000 \fi
5366 \ifnum \parencount=1 \rm \fi
5375 \ifnum\parencount=1
5404 \ifnum\parencount=0 \else \badparencount \fi
5405 \ifnum\brackcount=0 \else \badbrackcount \fi
5825 \ifnum\filenamelength>0
5910 \ifnum\secno=0
5912 \else \ifnum\subsecno=0
5914 \else \ifnum\subsubsecno=0
5921 \ifnum\secno=0
5923 \else \ifnum\subsecno=0
5925 \else \ifnum\subsubsecno=0
6074 \ifnum \count 1<256 \loop \fi