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s_expl.c (241051) s_expl.c (241516)
1/*-
2 * Copyright (c) 2009-2012 Steven G. Kargl
3 * All rights reserved.
4 *
5 * Redistribution and use in source and binary forms, with or without
6 * modification, are permitted provided that the following conditions
7 * are met:
8 * 1. Redistributions of source code must retain the above copyright

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22 * THEORY OF LIABILITY, WHETHER IN CONTRACT, STRICT LIABILITY, OR TORT
23 * (INCLUDING NEGLIGENCE OR OTHERWISE) ARISING IN ANY WAY OUT OF THE USE OF
24 * THIS SOFTWARE, EVEN IF ADVISED OF THE POSSIBILITY OF SUCH DAMAGE.
25 *
26 * Optimized by Bruce D. Evans.
27 */
28
29#include <sys/cdefs.h>
1/*-
2 * Copyright (c) 2009-2012 Steven G. Kargl
3 * All rights reserved.
4 *
5 * Redistribution and use in source and binary forms, with or without
6 * modification, are permitted provided that the following conditions
7 * are met:
8 * 1. Redistributions of source code must retain the above copyright

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22 * THEORY OF LIABILITY, WHETHER IN CONTRACT, STRICT LIABILITY, OR TORT
23 * (INCLUDING NEGLIGENCE OR OTHERWISE) ARISING IN ANY WAY OUT OF THE USE OF
24 * THIS SOFTWARE, EVEN IF ADVISED OF THE POSSIBILITY OF SUCH DAMAGE.
25 *
26 * Optimized by Bruce D. Evans.
27 */
28
29#include <sys/cdefs.h>
30__FBSDID("$FreeBSD: head/lib/msun/ld80/s_expl.c 241051 2012-09-29 16:40:12Z kargl $");
30__FBSDID("$FreeBSD: head/lib/msun/ld80/s_expl.c 241516 2012-10-13 19:53:11Z kargl $");
31
32/*-
33 * Compute the exponential of x for Intel 80-bit format. This is based on:
34 *
35 * PTP Tang, "Table-driven implementation of the exponential function
36 * in IEEE floating-point arithmetic," ACM Trans. Math. Soft., 15,
37 * 144-157 (1989).
38 *

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59static volatile const long double tiny = 0x1p-10000L;
60
61static const union IEEEl2bits
62/* log(2**16384 - 0.5) rounded towards zero: */
63o_threshold = LD80C(0xb17217f7d1cf79ab, 13, 11356.5234062941439488L),
64/* log(2**(-16381-64-1)) rounded towards zero: */
65u_threshold = LD80C(0xb21dfe7f09e2baa9, 13, -11399.4985314888605581L);
66
31
32/*-
33 * Compute the exponential of x for Intel 80-bit format. This is based on:
34 *
35 * PTP Tang, "Table-driven implementation of the exponential function
36 * in IEEE floating-point arithmetic," ACM Trans. Math. Soft., 15,
37 * 144-157 (1989).
38 *

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59static volatile const long double tiny = 0x1p-10000L;
60
61static const union IEEEl2bits
62/* log(2**16384 - 0.5) rounded towards zero: */
63o_threshold = LD80C(0xb17217f7d1cf79ab, 13, 11356.5234062941439488L),
64/* log(2**(-16381-64-1)) rounded towards zero: */
65u_threshold = LD80C(0xb21dfe7f09e2baa9, 13, -11399.4985314888605581L);
66
67static const double __aligned(64)
67static const double
68/*
69 * ln2/INTERVALS = L1+L2 (hi+lo decomposition for multiplication). L1 must
70 * have at least 22 (= log2(|LDBL_MIN_EXP-extras|) + log2(INTERVALS)) lowest
71 * bits zero so that multiplication of it by n is exact.
72 */
73INV_L = 1.8466496523378731e+2, /* 0x171547652b82fe.0p-45 */
74L1 = 5.4152123484527692e-3, /* 0x162e42ff000000.0p-60 */
75L2 = -3.2819649005320973e-13, /* -0x1718432a1b0e26.0p-94 */

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81P2 = 0.5,
82P3 = 1.6666666666666119e-1, /* 0x15555555555490.0p-55 */
83P4 = 4.1666666666665887e-2, /* 0x155555555554e5.0p-57 */
84P5 = 8.3333354987869413e-3, /* 0x1111115b789919.0p-59 */
85P6 = 1.3888891738560272e-3; /* 0x16c16c651633ae.0p-62 */
86
87/*
88 * 2^(i/INTERVALS) for i in [0,INTERVALS] is represented by two values where
68/*
69 * ln2/INTERVALS = L1+L2 (hi+lo decomposition for multiplication). L1 must
70 * have at least 22 (= log2(|LDBL_MIN_EXP-extras|) + log2(INTERVALS)) lowest
71 * bits zero so that multiplication of it by n is exact.
72 */
73INV_L = 1.8466496523378731e+2, /* 0x171547652b82fe.0p-45 */
74L1 = 5.4152123484527692e-3, /* 0x162e42ff000000.0p-60 */
75L2 = -3.2819649005320973e-13, /* -0x1718432a1b0e26.0p-94 */

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81P2 = 0.5,
82P3 = 1.6666666666666119e-1, /* 0x15555555555490.0p-55 */
83P4 = 4.1666666666665887e-2, /* 0x155555555554e5.0p-57 */
84P5 = 8.3333354987869413e-3, /* 0x1111115b789919.0p-59 */
85P6 = 1.3888891738560272e-3; /* 0x16c16c651633ae.0p-62 */
86
87/*
88 * 2^(i/INTERVALS) for i in [0,INTERVALS] is represented by two values where
89 * the first 53 bits of the significand is stored in hi and the next 53
90 * bits are in lo. Tang's paper states that the trailing 6 bits of hi should
89 * the first 53 bits of the significand are stored in hi and the next 53
90 * bits are in lo. Tang's paper states that the trailing 6 bits of hi must
91 * be zero for his algorithm in both single and double precision, because
92 * the table is re-used in the implementation of expm1() where a floating
91 * be zero for his algorithm in both single and double precision, because
92 * the table is re-used in the implementation of expm1() where a floating
93 * point addition involving hi must be exact. The conversion of a 53-bit
94 * double into a 64-bit long double gives 11 trailing bit, which are zero.
93 * point addition involving hi must be exact. Here hi is double, so
94 * converting it to long double gives 11 trailing zero bits.
95 */
96static const struct {
97 double hi;
98 double lo;
95 */
96static const struct {
97 double hi;
98 double lo;
99} s[INTERVALS] __aligned(16) = {
99/* XXX should rename 's'. */
100} s[INTERVALS] = {
100 0x1p+0, 0x0p+0,
101 0x1.0163da9fb3335p+0, 0x1.b61299ab8cdb7p-54,
102 0x1.02c9a3e778060p+0, 0x1.dcdef95949ef4p-53,
103 0x1.04315e86e7f84p+0, 0x1.7ae71f3441b49p-53,
104 0x1.059b0d3158574p+0, 0x1.d73e2a475b465p-55,
105 0x1.0706b29ddf6ddp+0, 0x1.8db880753b0f6p-53,
106 0x1.0874518759bc8p+0, 0x1.186be4bb284ffp-57,
107 0x1.09e3ecac6f383p+0, 0x1.1487818316136p-54,

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101 0x1p+0, 0x0p+0,
102 0x1.0163da9fb3335p+0, 0x1.b61299ab8cdb7p-54,
103 0x1.02c9a3e778060p+0, 0x1.dcdef95949ef4p-53,
104 0x1.04315e86e7f84p+0, 0x1.7ae71f3441b49p-53,
105 0x1.059b0d3158574p+0, 0x1.d73e2a475b465p-55,
106 0x1.0706b29ddf6ddp+0, 0x1.8db880753b0f6p-53,
107 0x1.0874518759bc8p+0, 0x1.186be4bb284ffp-57,
108 0x1.09e3ecac6f383p+0, 0x1.1487818316136p-54,

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